Using values to derive the general shape of a rotor

NoDOHC · 10-21-2010, 10:19 PM

You have to let alpha vary from -60 to 60 degrees. R is in inches from the center of the rotor. You have to plot it on polar coordinates.

I should send you an excel file outlining how it must be plotted.

Unfortunately, the shape does not match the curve that would fit the housing. I once thought as you do until I measured.

I will get you an equation for the dish too.

vex · 10-06-2012, 11:48 AM

So...I've been looking over all the things I never had time to finish when I was in school. Looks like I have a lot to get back to work on. Among which I have a parametric equation I think everyone would be glad to have:

x=e*cos*al+R*cos(al/3)+a*cos(al/3+d)
y=e*cos*al+R*sin(al/3)+a*sin(al/3+d)
R=105 mm
e=15 mm
a=3 mm (I'm not 100% on this one)
d=26.2

Change al = t in inventor and plot from 0-1080 (degrees). That will give you the rotor housing; from which you can develop a rotor.

Now to scour for the internal dimensions of the rotor...

10-21-2010, 10:19 PM	#16
NoDOHC The quest for more torque Join Date: Sep 2008 Location: Sheboygan, Wisconsin iTrader: (1) Posts: 855 Rep Power: 17	You have to let alpha vary from -60 to 60 degrees. R is in inches from the center of the rotor. You have to plot it on polar coordinates. I should send you an excel file outlining how it must be plotted. Unfortunately, the shape does not match the curve that would fit the housing. I once thought as you do until I measured. I will get you an equation for the dish too. __________________ 1986 GXL ('87 4-port NA - Haltech E8, LS2 Coils. Defined Autoworks Headers, Dual 2.5" Exhaust (Dual Superflow, dBX mufflers) 1991 Coupe (KYB AGX Shocks, Eibach lowering springs, RB exhaust, Stock and Automatic) Last edited by NoDOHC; 10-21-2010 at 10:23 PM..

10-06-2012, 11:48 AM	#17
vex RCC Loves Me Not You Join Date: Jul 2008 Location: Influx. iTrader: (6) Posts: 2,113 Rep Power: 19	So...I've been looking over all the things I never had time to finish when I was in school. Looks like I have a lot to get back to work on. Among which I have a parametric equation I think everyone would be glad to have: x=ecosal+Rcos(al/3)+acos(al/3+d) y=ecosal+Rsin(al/3)+asin(al/3+d) R=105 mm e=15 mm a=3 mm (I'm not 100% on this one) d=26.2 Change al = t in inventor and plot from 0-1080 (degrees). That will give you the rotor housing; from which you can develop a rotor. Now to scour for the internal dimensions of the rotor... __________________ The Official FC Radiator Thread My Project Thread: Cerberus CCVT Virginia Rotary Group