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Using values to derive the general shape of a rotor
Given:
R'=105 mm e=15mm Given that information what does the eccentricity dictate? From my experience with eccentricity it should be unit-less, but everything I've seen dictates that it's actually a distance unit for rotors. How do I use e? I 'assume' that the R' is the distance from the center of the circle to the edge of the rotor. Thoughts? |
If someone on this forum actually understands what vex is asking, I will give that person an e-cookie :) Because all i got was:
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just measure a rotor and figure it out?
im guessing 105mm is the arc radius of the face, and then the midpoint is offset 15mm (to the inside obviously) to clear the peanut shape. but i dunno, ive never even seen a rotor IRL lol |
Alright looks like I need to give RCC a refresher course in geometry. More specifically in conic sections.
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Furthermore e is the ratio between c and a, where a is the semi-major axis value or the distance between the center point and the longest edge, and c is a geometric constant which is resulted from the sqrt(a^2-b^2) where b is the semi-minor axis or the distance from the center to the shortest edge. Quote:
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Rotary History |
You are confusing yourself by thinking too hard. The eccentricity measurement you seek is actually the distance that the eccentric shaft is offset from center. (15 mm).
The R' is the distance from the center of the eccentric shaft to the intended apex of the rotor. These constants describe the rotor housing by a set of parametric equations. I have a parametric equation that I developed empirically by carefully measuring a rotor a while back. It should be pretty close (it yielded a net displacement of 653.8 cc per eccentric shaft revolution per rotor). I can get it to you, but it will require some explanation, as it was developed for a math model of the rotary engine that I was working on at the time. It is a function of R in terms of some theta (which I don't remember what angle theta represents now). I will PM you once I get to the bottom of this math. |
what do you plan to do with this data?
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3d model followed by a cfd analysis of the entire combustion process.
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Vex,
I wanted to do the same thing a while back. I have never been able to find proper equations or numbers to build a good model. I do however have a ROMER CMM with a perceptron laser scanner at my disposal, so i was hoping one day i could get some scans of a housing and some rotors. I build CAD models for RF signatures, CFD, and other analysis for a living. What software will you be using for modeling and analysis? Evan |
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I'm a little busy with school work at the moment so I may have to hold off on this for a little bit, but I'm still planning on doing it. |
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Good ole Inventor! Well if you get some good measurements please share! I currently use NX, Pro-e, solid edge, solid works, and inventor... We have a wide customer base, and because they all use different software we pretty much have them all.
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I am not good at computer drawing, or I would model them myself. PM or post here if you want the data. |
Bring it on!
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Shouldn't I be able to interpolate the correct shape of the rotor from the housing curve? If one apex is centered at the neck of the epitrochoid curve (narrowest center point), then the opposing apexes will be on the housing and the center of the face between them will be tangent to the opposing "neck". There is only one arc that will solve that. It will be somewhat untrue because the rotor wouldn't actually be modeled with apex seals... Need more data for that. |
roar, I wish I could be doing that right now... (I'm still swamped with Homework and projects for ship dynamics, boundary layer theory, astro mechanics, and a freakin' lab report!)
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